Integrand size = 21, antiderivative size = 115 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=-\frac {b c d^2}{6 x^2}-\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{3} b c d \left (c^2 d-6 e\right ) \log (x)+\frac {b \left (c^4 d^2-6 c^2 d e-3 e^2\right ) \log \left (1+c^2 x^2\right )}{6 c} \]
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Time = 0.11 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {276, 5096, 12, 1265, 907} \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=-\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{3} b c d \log (x) \left (c^2 d-6 e\right )+\frac {b \left (c^4 d^2-6 c^2 d e-3 e^2\right ) \log \left (c^2 x^2+1\right )}{6 c}-\frac {b c d^2}{6 x^2} \]
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Rule 12
Rule 276
Rule 907
Rule 1265
Rule 5096
Rubi steps \begin{align*} \text {integral}& = -\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-(b c) \int \frac {-d^2-6 d e x^2+3 e^2 x^4}{3 x^3 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{3} (b c) \int \frac {-d^2-6 d e x^2+3 e^2 x^4}{x^3 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{6} (b c) \text {Subst}\left (\int \frac {-d^2-6 d e x+3 e^2 x^2}{x^2 \left (1+c^2 x\right )} \, dx,x,x^2\right ) \\ & = -\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{6} (b c) \text {Subst}\left (\int \left (-\frac {d^2}{x^2}+\frac {d \left (c^2 d-6 e\right )}{x}+\frac {-c^4 d^2+6 c^2 d e+3 e^2}{1+c^2 x}\right ) \, dx,x,x^2\right ) \\ & = -\frac {b c d^2}{6 x^2}-\frac {d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2 d e (a+b \arctan (c x))}{x}+e^2 x (a+b \arctan (c x))-\frac {1}{3} b c d \left (c^2 d-6 e\right ) \log (x)+\frac {b \left (c^4 d^2-6 c^2 d e-3 e^2\right ) \log \left (1+c^2 x^2\right )}{6 c} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.03 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=\frac {1}{6} \left (-\frac {2 a d^2}{x^3}-\frac {b c d^2}{x^2}-\frac {12 a d e}{x}+6 a e^2 x-\frac {2 b \left (d^2+6 d e x^2-3 e^2 x^4\right ) \arctan (c x)}{x^3}-2 b c d \left (c^2 d-6 e\right ) \log (x)+\frac {b \left (c^4 d^2-6 c^2 d e-3 e^2\right ) \log \left (1+c^2 x^2\right )}{c}\right ) \]
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Time = 0.22 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.21
method | result | size |
derivativedivides | \(c^{3} \left (\frac {a \left (c x \,e^{2}-\frac {2 c d e}{x}-\frac {c \,d^{2}}{3 x^{3}}\right )}{c^{4}}+\frac {b \left (\arctan \left (c x \right ) c x \,e^{2}-\frac {2 \arctan \left (c x \right ) c d e}{x}-\frac {\arctan \left (c x \right ) c \,d^{2}}{3 x^{3}}-\frac {\left (-c^{4} d^{2}+6 c^{2} d e +3 e^{2}\right ) \ln \left (c^{2} x^{2}+1\right )}{6}-\frac {d \,c^{2} \left (c^{2} d -6 e \right ) \ln \left (c x \right )}{3}-\frac {c^{2} d^{2}}{6 x^{2}}\right )}{c^{4}}\right )\) | \(139\) |
default | \(c^{3} \left (\frac {a \left (c x \,e^{2}-\frac {2 c d e}{x}-\frac {c \,d^{2}}{3 x^{3}}\right )}{c^{4}}+\frac {b \left (\arctan \left (c x \right ) c x \,e^{2}-\frac {2 \arctan \left (c x \right ) c d e}{x}-\frac {\arctan \left (c x \right ) c \,d^{2}}{3 x^{3}}-\frac {\left (-c^{4} d^{2}+6 c^{2} d e +3 e^{2}\right ) \ln \left (c^{2} x^{2}+1\right )}{6}-\frac {d \,c^{2} \left (c^{2} d -6 e \right ) \ln \left (c x \right )}{3}-\frac {c^{2} d^{2}}{6 x^{2}}\right )}{c^{4}}\right )\) | \(139\) |
parts | \(a \left (x \,e^{2}-\frac {2 e d}{x}-\frac {d^{2}}{3 x^{3}}\right )+b \,c^{3} \left (\frac {\arctan \left (c x \right ) x \,e^{2}}{c^{3}}-\frac {2 \arctan \left (c x \right ) d e}{c^{3} x}-\frac {\arctan \left (c x \right ) d^{2}}{3 c^{3} x^{3}}-\frac {d \,c^{2} \left (c^{2} d -6 e \right ) \ln \left (c x \right )+\frac {c^{2} d^{2}}{2 x^{2}}+\frac {\left (-c^{4} d^{2}+6 c^{2} d e +3 e^{2}\right ) \ln \left (c^{2} x^{2}+1\right )}{2}}{3 c^{4}}\right )\) | \(140\) |
parallelrisch | \(-\frac {2 \ln \left (x \right ) b \,c^{4} d^{2} x^{3}-\ln \left (c^{2} x^{2}+1\right ) x^{3} b \,c^{4} d^{2}-b \,c^{4} d^{2} x^{3}-12 \ln \left (x \right ) b \,c^{2} d e \,x^{3}+6 \ln \left (c^{2} x^{2}+1\right ) x^{3} b \,c^{2} d e -6 x^{4} \arctan \left (c x \right ) b c \,e^{2}-6 x^{4} e^{2} a c +3 \ln \left (c^{2} x^{2}+1\right ) x^{3} b \,e^{2}+12 x^{2} \arctan \left (c x \right ) b c d e +12 a c d e \,x^{2}+b \,c^{2} d^{2} x +2 \arctan \left (c x \right ) b c \,d^{2}+2 a c \,d^{2}}{6 c \,x^{3}}\) | \(184\) |
risch | \(\frac {i b \left (-3 x^{4} e^{2}+6 x^{2} e d +d^{2}\right ) \ln \left (i c x +1\right )}{6 x^{3}}-\frac {2 \ln \left (x \right ) b \,c^{4} d^{2} x^{3}-\ln \left (-c^{2} x^{2}-1\right ) b \,c^{4} d^{2} x^{3}-3 i b c \,e^{2} x^{4} \ln \left (-i c x +1\right )-12 \ln \left (x \right ) b \,c^{2} d e \,x^{3}+6 \ln \left (-c^{2} x^{2}-1\right ) b \,c^{2} d e \,x^{3}+6 i b c d e \,x^{2} \ln \left (-i c x +1\right )-6 x^{4} e^{2} a c +3 \ln \left (-c^{2} x^{2}-1\right ) b \,e^{2} x^{3}+i b c \,d^{2} \ln \left (-i c x +1\right )+12 a c d e \,x^{2}+b \,c^{2} d^{2} x +2 a c \,d^{2}}{6 c \,x^{3}}\) | \(225\) |
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Time = 0.25 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.21 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=\frac {6 \, a c e^{2} x^{4} - b c^{2} d^{2} x - 12 \, a c d e x^{2} + {\left (b c^{4} d^{2} - 6 \, b c^{2} d e - 3 \, b e^{2}\right )} x^{3} \log \left (c^{2} x^{2} + 1\right ) - 2 \, {\left (b c^{4} d^{2} - 6 \, b c^{2} d e\right )} x^{3} \log \left (x\right ) - 2 \, a c d^{2} + 2 \, {\left (3 \, b c e^{2} x^{4} - 6 \, b c d e x^{2} - b c d^{2}\right )} \arctan \left (c x\right )}{6 \, c x^{3}} \]
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Time = 0.44 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.57 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=\begin {cases} - \frac {a d^{2}}{3 x^{3}} - \frac {2 a d e}{x} + a e^{2} x - \frac {b c^{3} d^{2} \log {\left (x \right )}}{3} + \frac {b c^{3} d^{2} \log {\left (x^{2} + \frac {1}{c^{2}} \right )}}{6} - \frac {b c d^{2}}{6 x^{2}} + 2 b c d e \log {\left (x \right )} - b c d e \log {\left (x^{2} + \frac {1}{c^{2}} \right )} - \frac {b d^{2} \operatorname {atan}{\left (c x \right )}}{3 x^{3}} - \frac {2 b d e \operatorname {atan}{\left (c x \right )}}{x} + b e^{2} x \operatorname {atan}{\left (c x \right )} - \frac {b e^{2} \log {\left (x^{2} + \frac {1}{c^{2}} \right )}}{2 c} & \text {for}\: c \neq 0 \\a \left (- \frac {d^{2}}{3 x^{3}} - \frac {2 d e}{x} + e^{2} x\right ) & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.17 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=\frac {1}{6} \, {\left ({\left (c^{2} \log \left (c^{2} x^{2} + 1\right ) - c^{2} \log \left (x^{2}\right ) - \frac {1}{x^{2}}\right )} c - \frac {2 \, \arctan \left (c x\right )}{x^{3}}\right )} b d^{2} - {\left (c {\left (\log \left (c^{2} x^{2} + 1\right ) - \log \left (x^{2}\right )\right )} + \frac {2 \, \arctan \left (c x\right )}{x}\right )} b d e + a e^{2} x + \frac {{\left (2 \, c x \arctan \left (c x\right ) - \log \left (c^{2} x^{2} + 1\right )\right )} b e^{2}}{2 \, c} - \frac {2 \, a d e}{x} - \frac {a d^{2}}{3 \, x^{3}} \]
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\[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=\int { \frac {{\left (e x^{2} + d\right )}^{2} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{4}} \,d x } \]
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Time = 0.78 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.23 \[ \int \frac {\left (d+e x^2\right )^2 (a+b \arctan (c x))}{x^4} \, dx=a\,e^2\,x-\frac {a\,d^2}{3\,x^3}+\frac {b\,c^3\,d^2\,\ln \left (c^2\,x^2+1\right )}{6}-\frac {b\,e^2\,\ln \left (c^2\,x^2+1\right )}{2\,c}-\frac {b\,c^3\,d^2\,\ln \left (x\right )}{3}-\frac {2\,a\,d\,e}{x}+b\,e^2\,x\,\mathrm {atan}\left (c\,x\right )-\frac {b\,c\,d^2}{6\,x^2}-\frac {b\,d^2\,\mathrm {atan}\left (c\,x\right )}{3\,x^3}-b\,c\,d\,e\,\ln \left (c^2\,x^2+1\right )+2\,b\,c\,d\,e\,\ln \left (x\right )-\frac {2\,b\,d\,e\,\mathrm {atan}\left (c\,x\right )}{x} \]
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